lxclock: fix a small memory leak

if (!name), we allocate an unnamed semaphore, but if we then fail to allocate/create the lock, we don't free this semaphore, and we just leak it. Signed-off-by: Tycho Andersen <tycho@tycho.ws>

lxclock: fix a small memory leak
8ecd7f2f · Tycho Andersen · Christian Brauner · a4922b61 · 8ecd7f2f
Unverified Commit 8ecd7f2f authored Feb 10, 2020 by Tycho Andersen Committed by Christian Brauner Mar 02, 2020
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lxclock.c src/lxc/lxclock.c +2 -0

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--- a/src/lxc/lxclock.c
+++ b/src/lxc/lxclock.c
@@ -169,6 +169,8 @@ struct lxc_lock *lxc_newlock(const char *lxcpath, const char *name)
 	l->type = LXC_LOCK_FLOCK;
 	l->u.f.fname = lxclock_name(lxcpath, name);
 	if (!l->u.f.fname) {
+		if (!name)
+			free(l->u.sem);
 		free(l);
 		l = NULL;
 		goto on_error;