Fix base register for stack variables in ARM integrated assembler.

When translating an Variable without a register, the code assumes the variable is on the stack using sp. This is still true. However, if it is a (derived class) StackVariable, the register defined by getBaseRegNum() should be used instead. BUG= https://code.google.com/p/nativeclient/issues/detail?id=4334 R=jpp@chromium.org, stichnot@chromium.org Review URL: https://codereview.chromium.org/1432453003 .

Fix base register for stack variables in ARM integrated assembler.
57586f73 · Karl Schimpf · cb504ca5 · 57586f73
Commit 57586f73 authored Nov 04, 2015 by Karl Schimpf
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IceAssemblerARM32.cpp src/IceAssemblerARM32.cpp +4 -2

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--- a/src/IceAssemblerARM32.cpp
+++ b/src/IceAssemblerARM32.cpp
@@ -236,8 +236,10 @@ DecodedResult decodeAddress(const Operand *Opnd, IValueT &Value) {
    const IOffsetT Offset = Var->getStackOffset();
    if (!Utils::IsAbsoluteUint(12, Offset))
      return CantDecode;
-    Value = decodeImmRegOffset(RegARM32::Encoded_Reg_sp, Offset,
+    RegARM32::GPRRegister BaseReg = RegARM32::Encoded_Reg_sp;
-                               OperandARM32Mem::Offset);
+    if (const auto *StackVar = llvm::dyn_cast<StackVariable>(Var))
+      BaseReg = decodeGPRRegister(StackVar->getBaseRegNum());
+    Value = decodeImmRegOffset(BaseReg, Offset, OperandARM32Mem::Offset);
    return DecodedAsImmRegOffset;
  }
  if (const auto *Mem = llvm::dyn_cast<OperandARM32Mem>(Opnd)) {